E.g. 25cm3 of 0.5 M HCl was used to neutralise 35cm3 of NaOH solution. Calculate the concentration of the sodium hydroxide solution in mol dm-3.
First write a balanced equation and decide what you know and what you need to know:
HCl + NaOH --> NaCl + H2O (HCl= 25cm3, 0.5 M), (NaOH= 35cm3)
Now work out how many moles of HCl you have:
Number of moles HCl = conc x vol. / 1000 = 0.5 x 25/1000 = 0.0125 moles
From the equation, you know 1 moles of HCl neutralises 1 mole of NaOH. So 0.0125 moles of HCl must neutralise 0.0125 moles of NaOH.
Now it's a doddle to work out the concentration of NaOH.
Concentration of NaOH = moles of NaOH X 1000/volume (cm3) = 0.0125 x 1000/35 = 0.36mol dm3
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