Tests with sodium hydroxide - NaOH - OH
For Cu2+: An insoluble (in excess NaOH) blue precipitate forms
Cu2+(aq)2OH(aq) --> Cu(OH)2(s)
For Fe2: An insoluble grey/green precipitate. After several minutes it oxidises to a rust coloured precipitate and iron (III) hydroxide.
Fe2+(aq)2OH-(aq) --> Fe9(OH)2(s)
For Fe3: An insoluble rust coloured precipitate forms.
Fe3+(aq)3OH-(aq) --> Fe(OH)3(s)
For Al3: A SOLUBLE white precipitate forms.
Al3+(aq)3OH-(aq) --> Al(OH)3(s)
For Ca2: An insoluble white precipitate forms
Ca2+(aq) +2OH-(aq) --> Ca(OH)2(s)
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