Analysis of a compound showed the following percentage composition by mass: Na=79.19%, O=25.81% [Ar: Na=23, O=16]. Find the empirical formula.
Find the molar ratio of atoms: Na - 79.19/23 = 3.443. O - 25.81/16 = 1.613. Divide by smallest number: 2:1. Empirical formula is Na2O.
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