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Card 6
Front
Analysis of a compound showed the following percentage composition by mass: Na=79.19%, O=25.81% [Ar: Na=23, O=16]. Find the empirical formula.
Back
Card 7
Front
Define molecular formula.
Back
Card 8
Front
Butane has 4C atoms and 10H atoms. What is it's molecular formula and empirical formula?
Back
Card 9
Front
A compound has an empirical formula of CH2 and a relative molecular mass of 56. What is its molecular formula?
Back
Card 10
Front
What is the equation for working out moles?
Back
See full card set