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Card 6

Front

Analysis of a compound showed the following percentage composition by mass: Na=79.19%, O=25.81% [Ar: Na=23, O=16]. Find the empirical formula.

Back

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Card 7

Front

Define molecular formula.

Back

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Card 8

Front

Butane has 4C atoms and 10H atoms. What is it's molecular formula and empirical formula?

Back

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Card 9

Front

A compound has an empirical formula of CH2 and a relative molecular mass of 56. What is its molecular formula?

Back

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Card 10

Front

What is the equation for working out moles?

Back

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