Chemistry Formula Unit 4 0.0 / 5 ? ChemistryCalculationsA2/A-levelEdexcel Created by: Katie LenetteCreated on: 18-12-12 18:55 Ph Ph=-log[H+] 1 of 24 [H+] from [OH-] [H+]=Kw / [OH-] 2 of 24 Ka weak acid Ka=([H+]eqm^2)/ [HA]eqm 3 of 24 [H+] strong acid [H+]eqm=[H+]init 4 of 24 [OH-] strong base [OH-]eqm=[OH-]init 5 of 24 Kb weak base Kb=([OH-]eqm^2 )/ [BOH]eqm 6 of 24 [H+] of buffer solution using Ka [H+]=(Ka[HA]) / [A-] 7 of 24 [OH-] of buffer solution using Kb [OH-]=(Kb [B] )/[BH+] 8 of 24 Ph if [salt]=[acid] Ka=[H+] so Ph=PKa 9 of 24 rate of reaction rate of reaction = 1/time 10 of 24 Rate ( rate equations ) rate=k [A]^(x)[B]^(y) 11 of 24 Arrhenius equation (k) k=Ae^(-Ea/RT) 12 of 24 S(total) S(total)=S(system)+ S(surroundings) 13 of 24 S(system) S(system)=S(products) - S(reactants) 14 of 24 S(surroundings) S(surroundings) =( -H x1000 )/ T 15 of 24 Enthalpy change of solution Enthalphy change of solution=-lattice energy +Enthalpy change of hydration 16 of 24 Kc of reaction xA+yB = mC+nD Kc=([C]^m [D]^n) / ([A]^x [B]^y) 17 of 24 Concentration Concentration = mol / volume 18 of 24 Kp of reaction xA+yB = mC+nD Kp=p(C)^m p(D)^n / p(A)^x p(B)^y 19 of 24 p(A) p(A)= (mol of A / total mol)x total pressure 20 of 24 Kc ( distribution constant ) Kc=( [in hydrocarbon solvent ] / [ in water]) 21 of 24 Atom economy atom economy = ( mass of desired product / mass of all reactants ) x100 22 of 24 S(total) alternative S(total) = Rln(K) 23 of 24 Splitting of peaks on NMR Splitting of peaks on NMR = number of hydrogens on adjacent carbons +1 24 of 24
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