—> as you go across period 4, Sc to Zn - the 3d subshell is being filled
—> the 4s subshell is filled before 3d (Cu & Cr are an exception)
—> 4s and 3d overlap as a result of this
—> when they react, they lose electrons to form a positive ions
—> they lose electron from the 4s subshell FIRST, then the 3d
—> this allows them to form ions with multiple oxidation states
—> all form a 2+ ion
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