Floating Point Representation

• Work out the exponent value in deanery
• From where the point was floated move it the amount of places identified by the exponent
• Add column headings and work out the value now with the new (implied) decimal point

8 Bit Mantissa 4 Bit Exponent

01101110 0101

Exponant is 5

0.1101110

Move the point 5 places right

011011.10

Work its value now which is...27.5

• Find the positive binary value
• If its negative, invert and add 1 to the right most column
• Normalise by taking of the excess 1's and adding them on the end as 0's
• Float the point
• Work out how many places the point moved, turn that number into a 4 bit binary code which is the exponent

-0.25

000000.01

111111.10

+1

111111.11

10000000

1.0000000 moved -5 places so exponent 1011 which is minus 5 in binary using twos complement