- Created by: aggy98
- Created on: 14-12-14 15:43
One method of determining the proportion of calcium carbonate in a coral is to dissolve a known mass of the coral in excess acid and measure the volume of carbon dioxide formed. In such an experiment, 1.13 g of coral was dissolved in 25 cm3 of hydrochloric acid (an excess) in a conical flask. When the reaction was complete, 224 cm3 of carbon dioxide had been collected over water using a 250 cm3 measuring cylinder.
Calculate the number of moles of CO2 produced:
- 224cm3/1000= 0.224 dm3.
Calculate the mass of 1 mole of CaCO3:
- Write equation(given in previos answer): CaCO3(s) + 2HCl(aq) = CaCl2(aq) + H2O(l) + CO2 (g)
- The Molar mass is: 40.1(ca) + 12(c) + 48(O3)= 100.1g