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Slide 2

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Make b the subject
a = bx + c
rearrange so that b is on the right
bx + c = a
-c -c -c from both sides
bx + c = a
bx = a - c ÷ both
÷x ÷x sides
bx = a - c by x
b=a­c
x…read more

Slide 3

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Make s the subject
n = m -3s
n = m - 3s
n + 3s = m add 3s to both sides
3s = m - n - n from both sides
3s = m - n divide both sides by 3
3…read more

Slide 4

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Make r the subject
p=q+r
s
q+r =p reverse to get r on left
s
q + r = sp multiply both sides by s
r = sp ­ q - q from both sides…read more

Slide 5

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Make b the subject
s = 3(a + b)
3(a + b) = s reverse to get b on left
3a + 3b = s multiply out the bracket
3b = s - 3a - 3a from both sides
3b = s - 3a divide both sides by 3
3…read more

Slide 6

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The area of a trapezium is
Find h (height) when
A = h(a + b)
A = 40 a = 10 b = 6 2
1st h(a
Make h the subject +How??
b)
then
rearrange =A
substitute
the in the
formula x2values
2
h=
h(a + 2A
b) = 2A divide by (a + b)
a+b
substitute in the values A = 40, a = 10, b = 6
h = 2 x 40 = 80 = 5
10 + 6 16…read more

Slide 7

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Preview of page 7

Comments

daviesg

Good resource, clear examples well presented with fun animation.  Might need some verbal explanation to go with it.

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