# Atoms and reactions

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- Created by: Celine West
- Created on: 07-04-14 11:14

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- Atoms and Reactions
- Atomic Structure
- atomic number
- number of protons in the nucleus

- mass number
- number of particles (protons and neutrons) in the nucleus

- electrons
- 0 mass, 1- charge

- neutrons
- 1 mass, 0 charge

- protons
- 1 mass, 1+ charge

- atomic number
- Atomic masses
- relative isotopic mass
- mass of an atom of an isotope

- relative atomic mass
- weighted mean mass of an atom of an element
- (% abundance)/ 100 X mass number

- relative molecular mass
- weighted mean mass of a molecule

- relative formula mass
- weighted mean mass of a formula unit

- relative isotopic mass
- The mole
- amount of any substance containing as many particles as there are carbon atoms in exactly 12g of carbon-12 isotope
- Avogadro constant
- 6.02x10^23

- Types of formula
- Empirical formula
- 1) find the molar ratio of atoms
- 2) divide by the smallest number
- 3) write empirical formula

- 2) divide by the smallest number
- 2) divide by the smallest number
- 3) write empirical formula

- 1) find the molar ratio of atoms
- Molecular formula
- 1) empirical formula
- 2) number of CH2 units in a molecule= Mr/empirical
- 3) molecular formula= no of units X CH2

- 2) number of CH2 units in a molecule= Mr/empirical
- 2) number of CH2 units in a molecule= Mr/empirical
- 3) molecular formula= no of units X CH2

- 1) empirical formula

- Empirical formula
- Standard solutions
- 1) find the amount in mol
- 2) convert mols to grams= m=n xM

- 2) convert mols to grams= m=n xM

- 1) find the amount in mol
- Moles and reactions
- Reacting masses
- 1) work out amount in moles
- 2) compare against equations
- 3) m=n x M

- 2) compare against equations
- 2) compare against equations
- 3) m=n x M

- 1) work out amount in moles
- Reacting masses and gas volumes
- 1) amount in moles
- 2) compare against equations
- 3) V = n x 24

- 2) compare against equations
- 2) compare against equations
- 3) V = n x 24

- 1) amount in moles

- Reacting masses
- Water of crystallisation
- 1) amount in mol of anhydrous
- 2) amount in mol of water
- 3) determine ratio

- 2) amount in mol of water
- 2) amount in mol of water
- 3) determine ratio

- 1) amount in mol of anhydrous
- Titration calculations
- always work out amount in mol
- compare against equation
- use appropiate formula

- Oxidation numbers
- uncombined element = 0
- combined oxygen= -2
- combined hydrogen= +1
- simple ion = charge on ion
- combined fluorine = -1

- Atomic Structure

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