# P4: Electric circuits

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A charge of 16.0 C passes through a bulb in 5.0 seconds. Calculate the current through the bulb.
I = Q / t. = 16.0 C / 5.0 s. = 3.2 A
1 of 6
The energy transferred to a bulb is 320 J when 64 C of charge passes through it. Calculate the potential difference across the bulb.
V = E / Q. = 320 J / 64 C. = 50 V
2 of 6
A 4.5 V battery is connected to a 1.0 resistor and a 5.0 in series with each other. Calculate the total resistance of the two resistors.
Total resistance = 1.0 + 5.0 = 6.0
3 of 6
A 4.5 V battery is connected to a 1.0 resistor and a 5.0 in series with each other. Calculate the current through the resistors.
Current = battery potential difference / total resistance. = 4.5 V / 6.0 . = 0.75 A
4 of 6
A circuit contains three resistors R(1) = 1 , R(2) = 2 , and R(3) = 6 connected in parallel to a 6 V battery. Calculate the current through each resistor.
I(1) = 6 A. I(2) = 3 A. I(3) = 1 A.
5 of 6
A circuit contains three resistors R(1) = 1 , R(2) = 2 , and R(3) = 6 connected in parallel to a 6 V battery. Calculate the current though the battery.
10 A
6 of 6

## Other cards in this set

### Card 2

#### Front

The energy transferred to a bulb is 320 J when 64 C of charge passes through it. Calculate the potential difference across the bulb.

#### Back

V = E / Q. = 320 J / 64 C. = 50 V

### Card 3

#### Front

A 4.5 V battery is connected to a 1.0 resistor and a 5.0 in series with each other. Calculate the total resistance of the two resistors.

### Card 4

#### Front

A 4.5 V battery is connected to a 1.0 resistor and a 5.0 in series with each other. Calculate the current through the resistors.

### Card 5

#### Front

A circuit contains three resistors R(1) = 1 , R(2) = 2 , and R(3) = 6 connected in parallel to a 6 V battery. Calculate the current through each resistor.