Computer Science Revision (PAPER 2)
- Created by: Kani.T
- Created on: 11-04-18 19:57
H | R | C | K | D | T | M | D | V | M | M | I | R | G | R | C | B | Q | R | T | M |
H | G | H | L | G | D | N | E | I | S | P | J | Y | T | O | S | W | E | L | W | W |
Q | L | I | D | T | E | I | E | H | Q | D | P | K | M | E | A | E | A | A | W | D |
B | O | T | E | R | N | W | N | R | E | A | G | M | L | L | A | E | L | N | S | F |
B | B | Y | K | G | L | B | R | B | P | Y | U | U | T | T | X | D | Y | E | T | W |
R | A | R | A | N | N | H | Y | R | B | T | R | S | H | C | N | Q | L | X | A | E |
M | L | B | B | H | H | A | U | N | A | N | R | I | E | O | U | U | H | L | C | F |
H | V | X | T | F | P | K | J | T | O | I | E | P | C | I | R | X | U | J | B | S |
P | A | C | P | H | I | F | I | I | F | R | T | E | S | E | F | M | A | J | W | W |
T | R | T | H | Q | W | V | T | S | A | I | S | T | V | A | R | T | G | K | G | S |
P | I | E | F | F | E | P | N | R | O | S | S | I | F | O | F | U | W | A | A | C |
C | A | U | O | R | R | A | C | N | N | T | T | I | F | Y | T | H | H | S | S | H |
E | B | X | U | O | G | H | H | A | H | A | Y | E | A | N | V | M | R | J | I | L |
O | L | L | S | R | Y | A | G | E | I | G | T | L | P | B | G | M | S | A | H | R |
V | E | B | O | C | N | R | O | C | W | A | K | Y | T | S | M | N | N | S | W | S |
S | A | M | H | D | O | R | O | I | R | I | L | Q | N | C | C | U | D | R | C | U |
G | E | A | L | M | E | S | D | T | R | P | X | W | H | N | T | U | A | N | H | F |
D | R | I | E | M | S | U | I | M | Y | G | J | C | W | S | V | Y | I | N | I | O |
T | N | D | E | A | O | B | A | O | Y | S | G | I | D | G | V | N | T | X | W | A |
G | C | K | S | K | S | D | G | X | K | B | X | H | U | Q | C | O | H | P | B | T |
U | L | Q | Q | S | E | E | M | Q | O | P | Q | T | N | X | Y | X | X | M | T | S |
Clues
- A diagram that shows the design of a system from the top down (9, 5)
- A Variable that is declared at the beginning of the program and is available anywhere in the program (6, 8)
- A+ (A.B) = A | A. (A+B) = A (10, 5)
- Frequency x Bit Depth x Channels (3, 4, 7)
- NOT(A AND B) = NOT(A) OR NOT(B) (2, 7, 6, 3)
- NOT(A OR B) = NOT(A) AND NOT(B) (2, 7, 5, 3)
- The process of dealing with events that cause the current subroutine to stop (9, 8)
- The sample rate should be at a frequency which is at least twice the value of the highest frequency in the sampled signal (8, 7)
- X. (Y.Z) = (X.Y) .Z | X+ (Y+Z) = (X+Y) +Z (11, 5)
- X.Y = Y.X | X+Y= Y+X (11, 5)
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