Amount of Substance

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Created by: JosephPHS
Created on: 28-01-23 15:16

Mole (Def)

1 Mole = 6.02 X 10^23 particles of the given species.

1 Mole is equivalent to the Mr or Ar of a substance in grams

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Moles (Mass)

Mass
Moles = --------
Mr

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Moles (Conc.)

Moles = Conc. X Volume

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Ideal Gas Equation

PV = nRT
P - Pressure (kPa)
V = Volume (m^3)
n = Moles
R = Ideal gas constant (8.31)
T = Temperature (°K (= °C - 273))

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Empirical Formula (Def)

Simplest Ratio of atoms within a compound

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Empirical Formula (Calculating from %)

1. Use total mass of 100g
2. Distribute based of % (25% = 25g)
3. Moles = Mass/Mr
4. Divide all mole values by smallest mole value
(If mole values were 1.445, 0.725 and 2.175, divide all by 0.725 to give 2.00, 1.00 and 3.01, empirical formula = X₂YZ₃)

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Theoretical Yield (Moles)

Mass
Theoretical Yield (Moles) = --------
Mr

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Percentage yield

Actual Yield
Percentage Yield = ------------------ X 100
Theoretical Yield

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% atom economy

mass of desired products
% atom economy = ----------------------------
total mass of reactants

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Other cards in this set

Card 2

Front

Mass
Moles = --------
Mr

Back

Moles (Mass)

Card 3

Front

Moles = Conc. X Volume

Back

Card 4

Front

PV = nRT
P - Pressure (kPa)
V = Volume (m^3)
n = Moles
R = Ideal gas constant (8.31)
T = Temperature (°K (= °C - 273))

Back

Card 5

Front

Simplest Ratio of atoms within a compound

Back

View more cards

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Amount of Substance