Physics OCR Chapter 10 (Electrical Circuits) 5.0 / 5 based on 1 rating ? PhysicsD.C. ElectricityA2/A-levelOCR Created by: CharliegageCreated on: 19-01-17 21:52 Kirchoff's Laws and Ohms Law Current cannot be created or destroyed Kirchoff's First Law Sum of current into a point = Sum of current out of that point (i.e. 10A = 5A + 5A) Based on the conservation of charge, no. of charge carriers into point must = number leaving that point Kirchoff's Second Law Around a closed loop, sum of E.M.F = sum of P.D Ohms Law For a metallic conductor kept at a constant temperature the current is directly proportional to p.d across its ends 1 of 5 Series Circuits Series Circuits A single loop, (1 pathway for current to travel) Current is the same in every position of circuit Rate of flow of charge remains the same, charge is not used up The E.M.F is shared across the components If resistance is equal share of e.m.f is equal If resistance of one is higher, has larger share of e.m.f Circuits with more than one source of e.m.f, add total e.m.f value, (i.e. 3V + 6V = 9V) If cell opposes another cell e.m.f's subtract, (i.e. 6V - 3V = 3V) 2 of 5 Parallel Circuits Parallel Circuits Provides multiple pathways, branches don't affect one another Amount of charge flow down a pathway depends on its resistance Current into junction = current out of the same junction Greater the resistance of branch the lower the current The p.d of every branch = must = the e.m.f of the power supply Due to Kirchoff's second law as each branch forms its own loop 3 of 5 Internal Resistance Internal Resistance All power sources have internal resistance, though some have higher than others Work has to be done for charge carriers to move through power source Resulting in some energy transferred 'lost' Not all energy transferred to charge is available for the circuit The p.d. at terminals (terminal p.d.) is less than e.m.f of the power source e.m.f = terminal p.d. + lost volts e.m.f = V + lost volts --> e.m.f = V + Ir --> e.m.f = I (R + r) Increased current = more lost volts = lower terminal p.d. 4 of 5 Potential Dividers Potential Dividers Two resistors connected in series, one resistor is Vout Vout can be varied from a range of 0 to terminal p.d. Kirchoff's second law total p.d of across resistors = terminal p.d. of power source Ratio between the two resistors --> if one has double the other receive 2/3 of total p.d V1/V2 = R1/R2 5 of 5
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