preparing a standard solution

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  • Created on: 10-05-13 08:05
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Preparing a standard solution
In preparing a standard solution, the following equipments and substances were used:
250cm3 beaker
250cm3 volumetric flask
Filter funnel
Stirring rod
Washing bottle
Distilled water
Anhydrous sodium carbonate (Na2CO3 0.1m)
Electronic balance
Eye protection
1. We weighed 250cm3 mass of sodium carbonate on an electronic balance by using a
spatula to get the accurate amount.
2. Then we put the weighed out 250cm3 sodium carbonate in a 250cm3 beaker.
3. We then added some distilled water into the beaker and stirred it with a stirring rod
till all the substances were dissolved completely.
4. We washed the plastic boat that originally contained the weighed out sodium
carbonate. The stirring rod is also rinsed with distilled water to wash out any sodium
carbonate on it. All the washings were done in the beaker.
5. Then carefully using the filter funnel, we poured in the solution of sodium carbonate
into a 250cm3 volumetric flask. After doing this, we poured in more distilled water till
it reached the graduation mark, using a pipette to add more water till the mark. The
volumetric flask is closed with a stopper.
6. Shake the solution in the flask vigorously but carefully.
7. Then leave the solution and set up your apparatus for your titration procedure.

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For the titration, the following equipment and substances are used:
Lab stand with a clamp
Indicator: methyl orange
Sulphuric acid (H2SO4)
White tile
Conical flask
Eye protector
1. We setup the titration apparatus. Putting the clamp on the stand and the burette on
the clamp, and the white tile below the stand.
2. Using a pipette, we took out 25Cm3 of the sodium carbonate solution we made
earlier and pour it into the conical flask.
3.…read more

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The equation for the reaction is: Na2CO3+H2SO4 Na2SO4+H2O
Mole ratio: 1:1
This is the formula used:
For Na2CO3
We know that the volume used is = 25cm3
We also know that the concentration is = 0.1mol
The number of moles will be= Concentration x volume
= 0.1 x 25
For H2SO4
We know that the volume is= 25.75cm3
We also know that the mole will be = 0.0025moles
The concentration will be = number of moles/ volume
= 0.0025
25.…read more


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