Quadratic Functions and Equations 0.0 / 5 ? MathematicsQuadratic Functions and EquationsInternational BaccalaureateNone Created by: TheThagomizer55Created on: 21-01-18 16:40 Solve by factorization: 4x^2 + 4x + 1 = 0 4x^2 + 4x + 1 = 0 --> (2x + 1) (2x + 1) = 0 --> (2x + 1)^2 = 0 --> 2x + 1 = 0 --> x = -1/2 1 of 6 Solve this equation by factorization: x(x + 10) = 4(x - 2) x(x + 10) = 4(x - 2) --> x^2 + 10x = 4x - 8 --> x^2 + 6x + 8 = 0 --> (x + 4) (x + 2) = 0 --> x = -4, x = -2 2 of 6 Complete the square: x^2 - 6x + 9 = 6 x^2 - 6x + 9 = 6 --> (x - 3)^2 = 6 --> x - 3 = ± √(6) --> x = 3 ± √(6) 3 of 6 Complete the square: x^2 - 3x - 1 = 0 x^2 - 3x - 1 = 0 --> x^2 - 3x = 1 --> x^2 - 3x + (9/4) = 1 + (9/4) --> (x + (3/2))^2 = (13/4) --> x - (3/2) = (± √13/2) --> x = ((3 ± √13) / 2) 4 of 6 Complete the square: 2x^2 + 8x = 6 2x^2 + 8x = 6 --> x^2 + 4x = 3 --> x^2 + 4x + 4 = 7 --> (x + 2)^2 = 7 --> x + 2 --> ± √(7) --> x = -2 ± √(7) 5 of 6 Solve using the quadratic equation: x^2 + 4x - 6 = 0 x^2 + 4x - 6 = 0 --> x = ((-4 ± √((4^2) - 4 (1) (-6)) / (2 (1))) --> x = ((-4 ± √(16 - 4 (-6))) / 2) --> x = ((-4 ± √(40)) / 2) --> x = ((-4 ± 2√(10)) / 2 --> x= -2 ± √(10) 6 of 6
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