Chemistry

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Hydrogen oxygen fuel cell
H2 +2OH- = 2H20 +2e. 1/2o2 + 2H2O + 2E = 2OH-. therefore: H2 + 1/2O2 = H20
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Colour change from Cu2+ to Cu(OH)2
Pale blue to pale blue
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Colour change from Co2+ to Co(OH)2
Pink to blue
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Colour change from Fe2+ to Fe(OH)2
Green to green
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Colour change from Fe3+ to Fe(OH)3
Yellow to brown
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Colour change from [Cu(H2O)]2+ + 4NH3 = [Cu(NH3)4(H2O)2]2+ + 4H2o
Pale blue solution to dark blue solution
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Colour change from [Cu(H2O)]2+ + 4Cl- = [CuCl4]2- + 6H2o
Pale blue solution to yellow solution
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Colour change from [Co(H2O)]2+ + 4Cl- = [CoCl4]2- + 6H2o
Pink solution to blue solution
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CDCl3
Deuterated solvent, gives no signal in NMR
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TMS
Standard for chemical shift measurements (1s = 0ppm)
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D20
Exchange with protons in OH and NH = no peak
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Chemical shift
A scale comparing frequency of NMR adsorption with frequency of reference peak of TMS at s=0ppm
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Si(CH3)4
Formula of standard reference compound in NMR. Responsible for 0 on NMR
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How is Tollens reagent made?
NaOH and silver nitrate = silver oxide + brown precip. NH3 added until precip dissolves
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Halogen carrier
Forms Cl+
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What if there is no molecular ion peak?
Compound is too unstable
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Base peak. Molecular ion peak
Most abundant fragment. Peak by unfragmented peak.
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Why triglycerides are soluble in non-polar solvents and not in water?
Van der Waals between triglyceride's and non-polar. Triglycerides cant hydrogen bond.
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Optical isomerism
Mirror image, non-superimposable, rotates plane polarised light in opposite direction to same degree.
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Cis/trans
Ligand donates a lone pair of e. Complex accepts a lone pair of e. To make a dative covalent bond.
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2nd IE of Ca2+ more endothermic than 1st of Ca+
Ca2+ ion smaller and greater attraction
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2nd EA of O2 is +
Energy required to overcome repulsion as O- are e are both negative
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1st IE of Ca is endothermic
Energy needed to overcome force of attraction between outer e and nucleus
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1st EA of O2 is endothermic
E attracted to nucleus
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Protein and nylon 6,6
Protein: different R groups, higher melting point, longer chain length
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MnO4- + 8H+ + 5Fe2+ = Mn2+ + 5Fe3+ + 4H2O
Purple to pink
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2Cu2+ + 4I- = 2Cu + I2
Makes a white precipitate and brown solution
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Other cards in this set

Card 2

Front

Colour change from Cu2+ to Cu(OH)2

Back

Pale blue to pale blue

Card 3

Front

Colour change from Co2+ to Co(OH)2

Back

Preview of the front of card 3

Card 4

Front

Colour change from Fe2+ to Fe(OH)2

Back

Preview of the front of card 4

Card 5

Front

Colour change from Fe3+ to Fe(OH)3

Back

Preview of the front of card 5
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