- Created by: Sabina__Ofori
- Created on: 22-10-18 14:11
Make 250 cm3 of a 0.100 mol dm-3 solution of sodium hydrogensulfate.
- Weighing Boat
- Volumetric Flask
- Sodium Hydrogensulfate Solid
- Filter Funnel
- Distilled (or de-ionised) water in a wash bottle
- Glass rod
- Digital mass balance (weighing scales), that read to at least 2 d.p.
1) Calculate the mass of sodium hydrogensulfate solid that will make 250 cm3 of a 0.100 mol dm3 sodium hyrdrogensulfate.
Do this by working out the number of moles of sodium hydrogensulfate needed, with the equation n = cv (number of moles = concentration x volume) and then using the number of moles required in the equation n = m ÷ Mr (number of moles = mass ÷ molecular mass) to work out the mass of solid needed.
2) Weigh a clean and dry weighing boat using the digital balance. Record the mass.
3) Leave the weighing boat on…