AS Chemistry - Unit 2
Organic chemistry - haloalkanes unit 2 of AQA AS chemistry
- Created by: Kaimlee
- Created on: 23-02-11 11:24
Haloalkanes
have an alkane skeleton with 1 or more halogen atoms in place of a hydrogen atom.
General Formula - CnH2n+1
Naming - CH3CH2CH2Cl = 1 - chloropropane
F - Fluoro if theres more than 1 halogen:
Cl - Chloro 2 = di
Br - Bromo 3 = tri
I - Iodo 4 = tetra
example: CH2BrCHBrCH2CH3 1, 2, di-bromobutane
Naming Questions
Q1.) Name: CH3CH2Cl
Q2.) Name: CH3CHFCHICH2I
Q3.) What is the general formula for a haloalkane?
Q4.) Describe what a haloalkane is?
Q5.) Name: CH3CHFCHCl2
Q6.) Name: CH3CHFCH3
Q7.) Name: CH3CF2CFHCH2CH3
Q8.) Name: CH3CH2CHBrCH3
Haloalkane - Properties
Bond Polarity: Haloalkane bond is polar - the halogen is more electronegative than the carbon atom.
Fluorine - most electronegative --> Iodine least (decreases down group)
Solubility, no - the polar bond isn't polar enough to make soluble in H2O
Boiling Point - depends on the no. of carbon atoms & halogen atoms
increases with chain length
Fluorine lower b.P ------> Iodine highest b.P - increases down group - larger molecules = stronger Van Der Waals' forces.
Haloalkanes higher b.P than alkanes - higer relative mass & more polar
Reactivity
2 Factors - bond polarity & bond enthalpy
Enthalpy: gets weaker going down the group
F - Strongest - small atom - e- pair strongly attracted (closer) = strong bond
I - weakest - large atom - e- pair futher distance from nucleus = weaker attraction
Polarity:
Halogens more electronegative than carbon - can be attracted by reagents that are electron rich areas - nucleophiles
(bond enthalpy more important than polarity)
Haloalkane Reactions
Making a Alcohol:
Reaction: Nucleophilic Subsitution
Conditions: warm & aqueous
Reagant: NaOH
Yield: low due to other unwanted reactions also taking place
Product: an alcohol
Draw Mechanism:
Haloalkane Reactions
Making a Nitrile:
Reaction: Nucleophilic Subsitution
Conditions: warm & alcoholic (ethanol)
Reagant: KCN
Product: Nitrile
Easily converted into carboxylic acid, increases C-C chain (C from alcohol)
Draw Mechanism:
Haloalkane Reactions
Making a Amine (Primary)
Reaction: Nucleophilic Subsitution
Conditions: Increased Pressure
Product: Amine NH3
Yield: low several different products are possible
Draw Mechanism:
Haloalkane Reactions
Making a Alkene
Reaction: Elimination
Conditions: Alcoholic (ethanol) insteed of H2O
Reagant: NaOH or KOH (OH acts as a base for the reaction)
More on Elimination Reaction
If the halogen atom is in a central position then there will be 2 possible products.
CH3CH2CHBrCH3 = a mixture of but-1-ene & but-2-ene
(but-2-ene the major product)
(but-1-ene the minor product)
Haloalkane Reactions
Making a Haloalkane
Reactants - Alkanes + Haloalkane
Conditions: UV light
Mechanism: Free Radical Subsitution
Free Radical - species with an unpaired electron, which makes them very reactive.
3 Step Mechanism
1. Initiation
2. Propogation (chain reaction)
3. Termination (2 free radicals react = a stable compound, slows down reaction)
Making a Haloalkane
This reaction is a v.poor way to make haloalkanes because it produces a number of products.
Chlorine is normally used but bromine can also be used:
Draw Bromine Mechanism:
Disruption of the Ozone
Chemicals called CFC's (chloro, fluoro compounds) were used in fridges and spray cans. CFC's excaped into the atmosphere the sunlight (UV) decomposed them to give chlorine radicals.
This radicals reacted with the Ozone molecules in a chain reaction.
1 chlorine radical could distory thousands of O(3) molecules.
Reduction in O(3) caused increase in diseases e.g. skin cancer, catarast.
so, CFC's were banded & replaced with less harmful substances MEPB
Exam Questions
Q1.) The haloalkanes become more reactive in nucleophilic substitution 1-chlorobutane < 1-bromobutane < 1-iodobutane explain why?
Q2.) What type of compund is formed when 1-bromobutane reacts with:
- aqueous OH:-
- alcoholic CN-
- conocentrated NH3
Q3.) Draw the mechanism for each?
Q4.) Explain what is meant by a nucleophile
Q5.) Explain what is meant by free radical?
Q6.) Write an equation for the initiation step use Cl then Br
Exam Questions
Q7.) Write two equations for the propagating step, using methane and chlorine as reactants?
Q8.) Write an equation for 2 possible terminating steps?
Q9.) Explain why the reaction is very inefficient?
Q10.) Write a mechanism for making a alcohol, state the conditions?
Q11.) Comment on the yield of this reaction?
Q12.) What is the name of the reaction which products an alkene?
Q13.) What other product is formed in this reaction?
Q14.) Why is but-2-ene described as the major product?
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