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AS Chemistry Chapter 2
Extension
Answers to teacher notes questions
examination-style
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1 (a) (i) 75.0 × 10­3 × 0.500 = 0.0375 (mol) 1

(ii) 21.6 × 10­3 × 0.500 = 0.0108 (mol) 1

(iii)0.0375 ­ 0.0108 = 0.0267 (mol) 1

(iv) m
oles of MgCO3 =…

Page 2

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AS Chemistry Chapter 2
Extension
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examination-style
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3 (a) moles HNO3 = 175 × 10­3 × 1.5 = 0.2625 mol 1

moles Pb(NO3)2 = ½ × 0.2625 = 0.131 mol 1 You must use the ratio from the
equation, i.e. 2 :…

Page 3

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AS Chemistry Chapter 2
Extension
Answers to teacher notes questions
examination-style
Answers Marks Examiner's tips

5 (a) (i) moles KNO3 = 1.00/101.1 = 9.89 × 10­3 1
(mol)

(ii) p
V = nRT or n = pV/RT 1

pV
moles O2 = n = 1
RT
­4
100 000
=…

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