Transition Metals 0.0 / 5 ? ChemistryTransition metalsA2/A-levelAQA Created by: benjaminfinchCreated on: 31-03-18 17:17 oxidation states of vanadium +5, +4, +3, +2 1 of 34 Oxidation State: +5. Ion: [VO2]+ 2 of 34 Oxidation State: +4. Ion: [VO]2+ 3 of 34 Oxidation State: +3. Ion: [V]3+ 4 of 34 Oxidation State: +2. Ion: [V]2+ 5 of 34 Colour of [VO2]+ Yellow 6 of 34 Colour of [VO]2+ Blue 7 of 34 Colour of [V]3+ Green 8 of 34 Colour of [V]2+ Violet 9 of 34 Most common oxidation state of Silver Ag+ (+1) 10 of 34 Reduction of Ag+ Ag+ + e- --> Ag 11 of 34 Tollens reagent [Ag(NH3)2]+ 12 of 34 Tollens and aldehyde reaction RCHO + 2[Ag(NH3)2]+ + 3OH- --> RCOO- + 2Ag + 4NH3 + 2H2O 13 of 34 Titration of Fe2+ and MnO4- equation MnO4- + 8H+ + 5Fe2+ --> Mn2+ + 4H2O + 5Fe3+ 14 of 34 Titration of [C2O4]2- and MnO4- equation 2MnO4- + 16H+ + 5(C2O4)2- ----> 2Mn2+ + 8H2O + 10CO2 15 of 34 [Cu(H2O)6]2+ (blue solution) with OH- or NH3 Cu(H2O)4(OH)2, a blue ppt is formed 16 of 34 [Cu(H2O)6]2+ (blue solution) with excess OH- no change 17 of 34 [Cu(H2O)6]2+ (blue solution) with excess NH3 [Cu(NH3)4(H2O)2]2+, a deep blue solution, is formed 18 of 34 [Cu(H2O)6]2+ (blue solution) with Na2CO3 a green blue ppt formed -- CuCO3 19 of 34 [Fe(H2O)6]2+ (green solution) with OH- or NH3 Fe(OH)2(H2O4), a green ppt formed 20 of 34 [Fe(H2O)6]2+ (green solution) with excess OH- no change 21 of 34 [Fe(H2O)6]2+ (green solution) with excess NH3 no change 22 of 34 [Fe(H2O)6]2+ (green solution) with Na2CO3 FeCO3, a green ppt is formed 23 of 34 [Al(H2O)6]3+ (colourless solution) with OH- / NH3 Al(OH)3(H2O)3 white ppt formed 24 of 34 [Al(H2O)6]3+ (colourless solution) with excess OH- [Al(OH)4(H2O)2]- colourless solution formed 25 of 34 [Al(H2O)6]3+ (colourless solution) with excess NH3 no change 26 of 34 [Al(H2O)6]3+ (colourless solution) with Na2CO3 Al(OH)3(H2O)3 white ppt formed and bubbles 27 of 34 [Fe(H2O)6]3+ (yellow solution) with excess OH-/NH3 Fe(OH)3(H2O)3 brown ppt formed 28 of 34 [Fe(H2O)6]3+ (yellow solution) with excess OH- no change 29 of 34 [Fe(H2O)6]3+ (yellow solution) with excess NH3 no change 30 of 34 [Fe(H2O)6]3+ (yellow solution) with Na2CO3 Fe(OH)3(H2O)3 brown ppt and bubbles 31 of 34 How do we get Vanadium to its various ox states? Vanadium in oxidation states: 4,3,2 are formed by the reduction of +5 ions by zinc in acidic solution 32 of 34 redox potential changing from a higher to lower ox state is influenced by... pH and ligand 33 of 34 redox potent. will be more ______ in more acidic solutions positive because the ion is more easily reduced 34 of 34
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