0.23g of sodium reacts with water to form 250cm³ of aqueous sodium hydroxide: 2Na(s)+2H₂O(l)->2NaOH(aq)+H₂(g). Work out how much gas is produced in cm³ and the concentration of sodium hydroxide produced. [Ar: Na-23, H-1, O-16]
1. n=m÷M=0.23÷23=0.01. 2. Na-2 mol so 0.01 mol, H₂-1 mol so 0.005 mol. V=nx24 000=0.005x24 000=120cm³. 3. NaOH- 2 mol so 0.01 mol. c(NaOH)=nx1 000÷V=0.01x1 000÷250=0.04 mol dm³.
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