Laws of Indicies 1.0 / 5 based on 1 rating ? MathematicsAlgebraASAQA Created by: Alice LambertCreated on: 07-09-13 10:12 a^3 x a^5 ^3+5 = a^8 1 of 12 a^7 / a^2 7 - 2 = 5 a^5 2 of 12 (a^2)^3 2x3=6 a^6 3 of 12 a^-5 1/a^5 4 of 12 a^0 1 5 of 12 a^1/2 square root a 6 of 12 a^1/3 cube root a 7 of 12 a^1/n n root a 8 of 12 a^2/3 (a^1/2 - square root a)^3 9 of 12 2n = 16 16 = 2^4 = 2^n n=4 10 of 12 3^2n-1 =27 3^2n-1=3^3 so 2n-1=3 n=2 11 of 12 8^n+1=16^n 8=2^3 16=2^4 so (2^3)^n 12 of 12
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