As rate = change in concentration/time, but the change in concentration is constant over all temperatures (measured as degree of cloudiness), so change in conc. = 1.
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Why does a small temperature change result in a large increase in the rate of reaction?
An increase in temperature leads to a large increase in the number of atoms/molecules with energy greater than or equal to Ea. So, there are many more successful collisions between molecules.
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How can the results be used to calculate activation energy?
Rearrange the Arrhenius equation to lnK = -Ea/R x 1/T + lnA. Plot a graph of y = lnK, x = 1/t, and gradient = -Ea/R. So Ea = -gradient x R. The gradient should always be -ve!
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3 things to remember for using a graph to calculate rate/Ea
1) Use a straight line of best fit (don't extrapolate). 2) Use all or most of the graph paper. 3) Use points far apart on the graph to calculate the gradient.
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What can lnK be replaced by on a graph?
ln(rate) as k is proportional to the rate of reaction.
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Other cards in this set
Card 2
Front
Why does a small temperature change result in a large increase in the rate of reaction?
Back
An increase in temperature leads to a large increase in the number of atoms/molecules with energy greater than or equal to Ea. So, there are many more successful collisions between molecules.
Card 3
Front
How can the results be used to calculate activation energy?
Back
Card 4
Front
3 things to remember for using a graph to calculate rate/Ea
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