Formula 0.0 / 5 ? ChemistryCalculationsA2/A-levelAQA Created by: Jennifer WelshCreated on: 11-03-14 20:12 Percentage error (error/reading) X 100 1 of 11 Total percentage error A% error + B% error 2 of 11 Ka (for weak acids) [H+] [X-] / [HX] OR [H+]^2 / [HX] 3 of 11 Kc [products]^n/[reactants]^n 4 of 11 pH -log[H+] 5 of 11 [H+] from pH shift log^ -pH 6 of 11 Kw [H+] [OH-] = 1x10^-14 mol^2dm^-6 at 298K 7 of 11 Kw (for water) [H+]^2 = 1x10^-14 mol^2dm^-6 at 298K 8 of 11 Ka (acidic buffer) [H+] [X-] / [HX] (X- comes from the salt) 9 of 11 Ka (half equivalence point) [H+] 10 of 11 Units for Kc RHS - LHS =Y then Y x (opposite sign 3)= T mol^Y dm^T 11 of 11
Comments
No comments have yet been made