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Why is this the case when substrate concentration is low?

What can you say about the order of reaction with respect to the substrate?

If the substrate concentration is high, the rate equation becomes...?

With plenty of substrate, the first step is no longer the ___ ___ ___, what is more important now is the speed of breakdown of __ and __?

The rate of this breakdown depends on __, so the reaction rate no longer depends on [S] so it is __ __ with respect to [S].