The concurrent substitution and elimination reactions of a halogenoalkane (eg 2-bromopropane with potassium hydroxide). or sodium hydroxide
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What is the reactant?
OH-
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What does it act as?
Base (proton accepter)
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What happens?
The hydroxide ion bonds the the H atom next to the halogen. Electrons move from the Hydrogen atom to form a double bond. Newly formed double bond repulses e- in carbon-X bond onto halogen so eliminated as -ve halide ion
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Overall eqn:
CH3CHBrCH3+OH-= CH3CH=CH2+Br-+H2O
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How do you favour elimination?
Ethanol as solvent and high temp and tertiary/secondary halogenoalkane and high conc of Noah/koh
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