Differentiation 4.5 / 5 based on 3 ratings ? MathematicsCalculusA2/A-levelEdexcel Created by: amyCreated on: 26-01-13 11:31 d/dx tan x sec(^2) x 1 of 24 d/dx cos x -sin x 2 of 24 d/dx sec x sec x tan x 3 of 24 d/dx cot x -cosec(^2) x 4 of 24 d/dx tan kx k.sex(^2) kx 5 of 24 d/dx sin kx k.cos kx 6 of 24 d/dx sec kx k.sec kx.tan kx 7 of 24 d/dx sin x cos x 8 of 24 d/dx cot kx -k.cosec(^2) kx 9 of 24 d/dx [f(x)]^n n.f'(x).[ f(x) ]^(n-1) 10 of 24 d/dx cosec kx -k.cosec kx.cot kx 11 of 24 d/dx e^x e^x 12 of 24 d/dx cosec x -cosec x.cot x 13 of 24 d/dx e^kx k.e^kx 14 of 24 d/dx [ f(x).g(y) ] g'(y).f(x).dy/dx + g(y).f'(x) 15 of 24 d/dx ln[ f(x) ] f'(x)/f(x) 16 of 24 d/dx a^x a^x.ln(a) 17 of 24 d/dx xy x.dy/dx + y 18 of 24 d/dx ln(x) 1/x 19 of 24 d/dx sec x cot x d/dx cosec x = -cosec x cot x 20 of 24 d/dx f(y) f'(y).dy/dx 21 of 24 d/dx y^n n.dy/dx.y^(n-1) 22 of 24 d/dx sec x tan x sec(^3)x + sec x.tan(^2)x = 2sec(^3)x- - sec x 23 of 24 d/dx cosec x.cot x -cosec(^3)x - cosec x.cot(^2)x = cosec x - 2cosec(^3)x 24 of 24
Core 3 - Chapter 6 - Differentiation using the product and quotient rule 5.0 / 5 based on 1 rating Teacher recommended
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