A cyclist travels at 3ms^-2, constant speed, as he starts to roll down a hill and accelerates constantly. During third second, he travels 6m. Calculate acceleration. How far does he travel during his fourth second?
v0=3, v1=3+a, v2=3+2a, v3=3+3a. s=(u+v)t/2. 6=6+5a/2 a=1.2ms^-2. v3= 6.6m/s, v4=7.8. s=(u+v)/2 = 7.2m.
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