Chemistry Topic 13 and 14

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One mole of any gas occupies 24dm^3 at room temperature and pressure (1 atmosphere.)
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T13- What is the molar volume?
The space that one mole of gas takes up.
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T13- What is the conversion between cm^3 and dm^3?
1000 cm^3 = 1 dm^3
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T13- What is the triangle to use regarding volumes?
Volume on top with number of moles and 24 below.
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T13- How do you find volumes in reactions?
You calculate masses in reactions, and then convert to volume.
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T14- Define 'concentration.'
Moles per unit volume. (Amount of particles per volume.)
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T14- What is the unit for concentration?
mol/L= mol/dm^3 = mol dm^-3
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T14- What is the triangle used regarding concentration?
Number of moles at the top, concentration below to the left and Volume below to the right.
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T14- How would you find g/ dm^3?
Simply divide the mass by the volume (maybe RTP where 1 mole of gas = 24 dm^3)
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T14- How would you convert from mol/ dm^3 to g/dm^3?
Use the triangle where mass is on top, and number of moles and relative formula mass are below.
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Other cards in this set

Card 2

Front

T13- What is the molar volume?

Back

The space that one mole of gas takes up.

Card 3

Front

T13- What is the conversion between cm^3 and dm^3?

Card 4

Front

T13- What is the triangle to use regarding volumes?

Card 5

Front

T13- How do you find volumes in reactions?