Amount of substance

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  • Created by: charley
  • Created on: 30-08-18 14:46
Avogadro constant
The number of atoms per mole of the carbon-12 isotope. 6.02x10^23/mol
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Moles, mass and molar mass equation
Moles=mass/molar mass
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Empirical formula
The simplest whole number ratio of atoms of each element present in a compound
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Molecular formula
The number and type of atoms of each element in a molecule
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Anhydrous
Containing no water molecules
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Water of crystallisation
Water molecules that are bonded into a crystalline structure of a compound
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How do you calculate the water of crystallisation?
First work out the moles of the anhydrous salt then calculate the moles of water. Find the smallest whole number ratio, this is the formula for the hydrated salt
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Moles, concentration and volume equation
Moles = volume x concentration
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Standard solution
A solution of known concentration
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Molar gas volume
The volume per mole of gas molecules at a stated temperature and pressure. 24dm^3 at RTP
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Amount, volume and molar gas volume equation
Amount = volume/molar gas volume (24)
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The ideal gas equation
pV=nRT. R=8.314J/mol/K, temperature is in K, pressure is inPa and volume is in m^3
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Stoichiometry
The ratio of the amount of each substance in a chemical equation
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Percentage yield equation
Percentage yield = (actual yield/ theoretical yield) x 100
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Limiting reagent
The reactant that will be used up first, stopping the reaction
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Atom economy
A measure of how well atoms have been utilised, assuming yield is 100%
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Atom economy equation
Atom economy = (the sum of the molar masses of desired products / the sum of the molar masses of all products) x 100
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Other cards in this set

Card 2

Front

Moles=mass/molar mass

Back

Moles, mass and molar mass equation

Card 3

Front

The simplest whole number ratio of atoms of each element present in a compound

Back

Preview of the back of card 3

Card 4

Front

The number and type of atoms of each element in a molecule

Back

Preview of the back of card 4

Card 5

Front

Containing no water molecules

Back

Preview of the back of card 5
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