Working Out Activation Energy


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  • Created by: LenBon
  • Created on: 08-06-12 14:47

Find out the rates of reaction

This is done by using the time taken (which should be supplied) in:


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Convert temperatures to Kelvin

This is done by:

Celcius + 273

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Use the Kelvin Temperature

It is used with:


. . .to produce 1/T/K-1

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Plot the graph

Use appropriate scale (so the line covers hald the graph) with:

lnk against 1/T/K-1

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Find the gradient of the line

This is done by drawing a triangle, from the start to finish underneath the line and working out the X and Y lengths. Then use:


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Find Activation Energy

This is done by using:


This equates to (for the none mathmeticians):

Ea(jmol-1) = gradientx8.31

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