Working Out Activation Energy

A

?
  • Created by: LenBon
  • Created on: 08-06-12 14:47

Find out the rates of reaction

This is done by using the time taken (which should be supplied) in:

1/time

1 of 6

Convert temperatures to Kelvin

This is done by:

Celcius + 273

2 of 6

Use the Kelvin Temperature

It is used with:

1/Temperature

. . .to produce 1/T/K-1

3 of 6

Plot the graph

Use appropriate scale (so the line covers hald the graph) with:

lnk against 1/T/K-1

4 of 6

Find the gradient of the line

This is done by drawing a triangle, from the start to finish underneath the line and working out the X and Y lengths. Then use:

Y/X

5 of 6

Find Activation Energy

This is done by using:

K=Ae-Ea/RT

This equates to (for the none mathmeticians):

Ea(jmol-1) = gradientx8.31

6 of 6

Comments

No comments have yet been made

Similar Chemistry resources:

See all Chemistry resources »See all Energetics resources »