Working Out Activation Energy A 0.0 / 5 ? ChemistryEnergeticsA2/A-level Created by: LenBonCreated on: 08-06-12 14:47 Find out the rates of reaction This is done by using the time taken (which should be supplied) in: 1/time 1 of 6 Convert temperatures to Kelvin This is done by: Celcius + 273 2 of 6 Use the Kelvin Temperature It is used with: 1/Temperature . . .to produce 1/T/K-1 3 of 6 Plot the graph Use appropriate scale (so the line covers hald the graph) with: lnk against 1/T/K-1 4 of 6 Find the gradient of the line This is done by drawing a triangle, from the start to finish underneath the line and working out the X and Y lengths. Then use: Y/X 5 of 6 Find Activation Energy This is done by using: K=Ae-Ea/RT This equates to (for the none mathmeticians): Ea(jmol-1) = gradientx8.31 6 of 6
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