Module 2, Chapter 3
- Created by: Foxswimmer01
- Created on: 18-10-18 18:23
3.1 Amount of substance and the mole
The Mole
One mole contains 6.02x1023 particles.
Avagadro constant = NA = 6.02x1023 mol-1
This is the number of particles in each mole of carbon-12.
1 mole of atoms of an element is its relative atomic mass in grams
Molar Mass
Molar mass is the mass per mole of a substance. Units are g mol-1
Amount of substance (n) = mass (m) / molar mass (M)
3.2 Determination of Formulae
Molecular Formulae
The number of atoms of each element in a molecule.
Empirical Formulae
The simplest whole-number ratio of atoms of each element in a compound.
Relative Molecular Mass
Compares the mass of a molecule with the mass of an atom of carbon-12.
Relative Formula Mass
Compares the mass of a formula unit with the mass of an atom of carbon-12. Calculated by adding the relative atomic masses of the elements in the empirical formula.
3.2 Determination of Formulae
Finding formulae by experiment
Empirical formula from mass:
- Convert mass into moles using n = m / M
- Find smallest whole-number ratio, divide by smallest whole number ratio
- Write empirical formula
Determination of a molecular formula:
- Convert % by mass into moles of atoms using n = m / M
- Find smallest whole-number ratio and empirical formula
- Write relative mass of empirical formula
- Find number of units in one molecule
- Write molecular formula
3.2 Determination of Formulae
Hydrated Salts
Many coloured salts are hydrated – water molecules are part of their crystalline structure.
This water is water of crystallisation.
When the water of crystallisation is removed through heating the compound, anhydrous crystals are left.
3.3 Moles and Volume
Volume
Volume is measured in:
· cm3 or ml – 1cm3 = 1ml
· dm3 or litre – 1dm3 = 1000cm3 = 1000ml = 1l
Moles and solutions
n = c x V
Moles = Concentration x Volume
Or if volume is in cm3 divide it by 1000
To convert between mass concentrations, g dm-3 , and concentrations in mol dm-3, you need to convert between moles and grams.
3.3 Moles and Volume
Standard solution
A solution of known concentration. Which is prepared by dissolving an exact mass of the solute in a solvent and making up the solution to an exact volume.
Moles and gas volumes
Molar gas volume is the volume per mole of a gas molecule at a stated temperature and pressure.
RTP – Room Temperature Pressure is about 20 degrees Celsius and 101kPa (1 atm).
At RTP, 1 mole of gas molecules has a volume of approximately 24.0 dm3, making the molar gas volume at RTP = 24.0 dm3 mol-1.
When the volume is in cm3, divide by 24000.
When the volume is in dm3 divide by 24.0.
3.3 Moles and Volume
Ideal Gas Equation
pV = nRT
- R = ideal gas constant = 8.314 J mol-1 K-1
- p = pressure = Pa
- V = volume = m3
- n = amount of gas molecules = mol
- T = temperature = K
Converting between units
- cm3 to m3 = x10-6
- dm3 to m3 = x10-3
- oC to K = +273
- kPa to Pa = x103
3.4 Reacting Quantities
Stoichiometry
The ratio of the amount, in moles, of each substance.
Quantities from amounts and equations
1. Work out amount in moles of everything you can.
2. Use the equations to work out the amount of moles of the unknown chemical.
3. Work out the unknown information which is required.
3.4 Reacting Quantities
Percentage Yield
The maximum possible amount of product produced is the theoretical yield.
The theoretical yield is unlikely to be achieved because:
· The reaction may not have ‘finished’
· There may be side reactions occurring
· Some of the product may be lost in transferring and purifying
The actual yield is usually lower than the theoretical yield.
Percentage yield = (actual yield / theoretical yield) x 100 %
The limiting reagent – the reactant which is not in excess so will be completely used up first and will cause the reaction to stop.
3.4 Reacting Quantities
Atom Economy.
How well atoms have been utilised in a chemical reaction,
Atom economy =
(sum of molar masses of desired products / sum of molar masses of all products) x 100%
Higher atom economies mean that reactions are more efficient and produce less waste.
Atom economy also reflects the sustainability of reactions and processes.
Related discussions on The Student Room
- How's FM1 - Edexcel? »
- 80% in final year »
- Tips for physical A level chemistry OCR A? »
- Grade Growth Chronicles | From C's to A's (23-24) »
- Low 2.2 in 2nd yr, can I get a 2.1/1st in 3rd yr?… »
- Open University Final Grading? »
- 3rd year average »
- Calculating Final Grade »
- Open University predicted grade! »
- Will I able to get a first »
Comments
No comments have yet been made