quadratics 0.0 / 5 MathematicsQuadratic equationsGCSEEdexcel Created by: samranCreated on: 03-10-19 22:21 solving quadratic equations x²+10x+24=0 1. find a pair of numbers that can be timesed together to give 24 but added together to give 10 2. then put in brackets (x+6)(x+4) to get your final answers you have to find the opposite of the numbers in the bracket (x-6)(x-4) 1 of 4 solving quadratic equations 2 2x²+13x+15 1. 15 x 2 = 30 2. find common factors of 30 that add toegther to give 13 e.g. 10 and 3 3. put values back into equation 2x²+10x+3x+15 4. split in half and factorise 2x(x+5) 3(x+5) 5. first value is (2x+3) 6. second value is (x+5) 2 of 4 quadratic equations using quadratic formula 1. first write out the formula quadratic formula: x= -b=+-√b²-4ac÷2a 2. then put the values be careful and remeber the + and - a=4x²+7x+3=0 -7+-√7²-4x4x3÷2x4 3. solve 4. you will have two values 5. x= -0.75 x=-1 3 of 4 simultaneous equations 3x-3y=3 2x-8y=-34 1. make x or y the same 6x-6y=6 6x-24y=-102 18y÷18= 102÷18 y=6 2. put y value in 3x-18=3 3x=21 x=7 4 of 4

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