Assume the overall volume for titre 2 = 37.60cm3
Assume the volume for titre 1 = 23.80cm3
Assume the concentration of HCl = 0.1moldm-3
If the concentration of HCl is known then the moles of HCl can be determined. The ratio of HCl to hydrogencarbonate = 1:1 so the moles of hydrogencarbonate will be known. This is equal to the moles of carbonate.
Volume of HCl which reacts with HCO3- = 37.60 - 23.80 = 13.80cm3
Volume of HCl which reacts with CO32- = 13.80cm3
Volume of HCl which reacts with NaOH = 10.00cm3
2NaOH + CO2 --> Na2CO3 + H2O
Moles of HCl which reacts with Na2CO3 = 0.1 x 13.80/1000 = 0.00138
Moles of Hcl which reacts with NaOH = 0.1 x 10/1000 = 0.001
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