Chemistry C3

These are the necessary formulae concerning titrations in this topic, with a couple of questions at the end.

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Formulae

No. particles = no. moles * 6*10²³

No. moles = mass / formula mass MASSES

No. of moles of gas = volume of gas (cm³) / 24,000cm³ GASSES

No. moles of gas = volume of gas (dm³) / 24dm³ GASSES

No. moles = concentration (mol/dm³) * volume (dm³)  SOLUTIONS

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Questions

What mass of Calcium Carbonate is needed to neutralise 2dm³ of 0.500 mol/dm³  hydrochloric acid?

CaCO3(s) + 2HCl(aq) --> CaCl2(aq) + H2O(l) + CO2(g)

What volume of 2mol/dm³  H2SO4 is needed to neutralise 5kg of sodium carbonate?

Na2CO3(s) + H2SO4(aq) --> Na2SO4(aq) + H2O(l) +CO2(g)

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Comments

Sonam Dubb

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Hey

This makes a lot more sense than the notes that I have. Just one thing, could you put the answers to the questions up because I just wanna make sure i got them right.

Thanks

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