Mechanics Notes for CCEA

I made these notes from the examples my maths teacher gave over the course of the year before my Ad Maths Exam. It helped me a lot to work through the examples, and I've added notes where I found easier ways to do some things.

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[PAPER 2 MECHANICS NOTES]
Mechanics
Notes for CCEA Additional Mathematics
Examples and explanations of the Mechanics course for CCEA
Additional Mathematics Paper 2
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PAPER 2 MECHANICS NOTES]
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PAPER 2 MECHANICS NOTES]
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PAPER 2 MECHANICS NOTES]
Motion with Constant Acceleration
Displacement-Time Graphs
Displacement = speed in a given direction = velocity (m/s)
Average velocity =
Average speed =
Velocity-Time Graphs
Gradient = acceleration
Area under curve = total distance
Continuous line = constant velocity
NOTE: Flat areas are not areas of rest!
Equations of Motion with constant velocity
Where velocity or acceleration is constant:
, will yield:
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PAPER 2 MECHANICS NOTES]
Vertical Motion under Gravity
NOTE: Gravity is 10m/s2 for CCEA examinations
Example 1: A stone is catapulted vertically upwards at a velocity of 24.5m/s. For how long will it exceed 29.4m?
Remembering that gravity is working DOWN, we use SUVAT to choose a formula.
Therefore, we will use
Substituting will yield:
Therefore, between 2 and 3 seconds, the stone is above the limit.
Newton's Laws
1.…read more

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PAPER 2 MECHANICS NOTES]
As acc. Is upwards, 84N is greater than B.
Friction
When an object is `on the point' of tipping, friction is said to be LIMITING.
where R = Normal Reaction
= Coefficient of Friction NOTE:
Example 1: A body of mass 5kg accelerates along a rough horizontal surface at 1.32m/s2, under the friction of a
horizontal force of magnitude 36N. Find the coefficient of friction.…read more

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PAPER 2 MECHANICS NOTES]
The Inclined Plane
Example 1: A body of mass 4kg rests on a rough plane inclined at 40°. When the body is pulled down by a 38N
force, inclined at 21° to the plane, it experiences a constant frictional force of 3N. Find A and the Normal
Reaction, R.
Friction on the Inclined Plane
Example 1: An object of mass 5kg rests on a rough plane inclined at 21° to the horizontal.…read more

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PAPER 2 MECHANICS NOTES]
Connected Particles
Example 1: A large train has an engine of 8kg capable of exerting a force of 60N, and 3 carriages of mass 1kg,
3kg, and 4kg. Calculate a, and the tensions T1, T2 and T3 in the couplings.
Using , we get:
T1 = 4N T2 = 12N T3 = 28N
Pulleys
Example 1: Particles of mass 4kg and 2kg are connected using a light inextensible sting which passes over a
smooth, fixed pulley. Find a and Tension.…read more

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PAPER 2 MECHANICS NOTES]
Equating: 20 =6a
Tension: 40 - T= 4(3.33)
T = 26.66 N
Resultant Forces and Components
Gives that
Example 1: A mass of 5kg is supported by two light inextensible strings attached at points P and Q. The mass
rests in equilibrium. Find the tension T and S, when they lie 30° and 45° from the horizontal.…read more

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PAPER 2 MECHANICS NOTES]
NOTE: This can get messy, so check your answer.
Moments
Law 1: To ensure equilibrium, the sum of the components must be zero. Total up = Total down.
Law 2: The sum of moments about a point must equal zero. Total clockwise= Total anticlockwise.
Terminology
Light- negligible mass
Uniform- Weight acts at centre
Smooth- no fiction
On the point- no support at A if it is tilting about B and vice versa.…read more

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