Q. Find the drift velocity of electrons of wire diameter of 0.32mm, current of

2.4A and where n is 8.5×10 power of -23 M -3

Solution

First we write the equation: A= nAVq and see what parts we got. In the

question we have n, diameter of the wire and the charge. Now we can

rearange the equation:

V= I/ nAq but there is one other step- we need to find the area of the wire as

without it its not possible to find the velocity.

Using formula for area : r squared.

0.32/2=0.16mm

Convert to metres which is simply 0.16×10power of -3 m

Now we use area formula :

×(0.16×10 power of -3)squared = 8.04× power of -8 metres squared. Now that

we have the area we can find the drift velocity!…read more

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