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January 2007 Sacred Heart
of Mary Girls' School QUADRATIC EQUATIONS
1

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7. The equation x 2 + kx + ( k + 3 )
= 0 , where k is a constant, has different real roots.
(a) Show that
k 2 - 4 k - 12 > 0 .
(2)
(b) Find the set of possible values of k.…

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Leave blank 8. The equation
x 2 + kx + 8 = k has no real solutions for x.
(a) Show that k satisfies .
(3)
(b) Hence find the set of possible values of k.
(4)
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Leave blank 7. The equation kx2 + 4x + (5 ­ k) = 0, where k is a constant, has 2 different real
solutions
for x.
(a) Show that k satisfies
k2 ­ 5k + 4 > 0.
(3)
(b) Hence find the set of possible values of k.
(4)…

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Pages in this set

Page 1

Preview of page 1

Page 2

Preview of page 2
January 2007 Sacred Heart
of Mary Girls' School QUADRATIC EQUATIONS
1

Page 3

Preview of page 3

Page 4

Preview of page 4
Leave blank

7. The equation x 2 + kx + ( k + 3 )
= 0 , where k is a constant, has different real roots.
(a) Show that
k 2 - 4 k - 12 > 0 .
(2)
(b) Find the set of possible values of k.…

Page 5

Preview of page 5
___________________________________________________________________________
___________________________________________________________________________
___________________________________________________________________________
___________________________________________________________________________
___________________________________________________________________________
___________________________________________________________________________
___________________________________________________________________________
___________________________________________________________________________
___________________________________________________________________________
12


*H26107A01224*

Page 6

Preview of page 6

Page 7

Preview of page 7
Leave blank 8. The equation
x 2 + kx + 8 = k has no real solutions for x.
(a) Show that k satisfies .
(3)
(b) Hence find the set of possible values of k.
(4)
___________________________________________________________________________
___________________________________________________________________________
___________________________________________________________________________
___________________________________________________________________________
___________________________________________________________________________
___________________________________________________________________________
___________________________________________________________________________
___________________________________________________________________________
___________________________________________________________________________
___________________________________________________________________________
___________________________________________________________________________
___________________________________________________________________________
___________________________________________________________________________…

Page 8

Preview of page 8
___________________________________________________________________________
___________________________________________________________________________
___________________________________________________________________________
___________________________________________________________________________
___________________________________________________________________________
___________________________________________________________________________
12


*N25561A01224*

Page 9

Preview of page 9

Page 10

Preview of page 10
Leave blank 7. The equation kx2 + 4x + (5 ­ k) = 0, where k is a constant, has 2 different real
solutions
for x.
(a) Show that k satisfies
k2 ­ 5k + 4 > 0.
(3)
(b) Hence find the set of possible values of k.
(4)…

Comments

No comments have yet been made