AQA AS 2 BIO June 2012 Question Paper

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For Examiner's Use
Centre Number Candidate Number
Surname
Other Names
Examiner's Initials
Candidate Signature
Question Mark
General Certificate of Education
1
Advanced Subsidiary Examination
June 2012 2
3
Biology BIOL2 4
Unit 2 The variety of living organisms 5
6
Monday 21 May 2012 1.30 pm to 3.15 pm
7
8
For this paper you must have:
l a ruler with millimetre measurements.
9
l a calculator.
TOTAL
Time allowed
l 1 hour 45 minutes
Instructions
l Use black ink or black ball-point pen.
l Fill in the boxes at the top of this page.
l Answer all questions.
l You must answer the questions in the spaces provided. Do not write
outside the box around each page or on blank pages.
l You may ask for extra paper. Extra paper must be secured to this
booklet.
l Do all rough work in this book. Cross through any work you do not
want to be marked.
Information
l The maximum mark for this paper is 85.
l You are expected to use a calculator, where appropriate.
l The marks for questions are shown in brackets.
l Quality of Written Communication will be assessed in all answers.
l You will be marked on your ability to:
­ use good English
­ organise information clearly
­ use scientific terminology accurately.
(JUN12BIOL201) BIOL2
WMP/Jun12/BIOL2

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Page 2

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Answer all questions in the spaces provided.
1 (a) Flatworms are small animals that live in water. They have no specialised gas exchange
or circulatory systems.
The drawing shows one type of flatworm.
1 mm
1 (a) (i) Name the process by which oxygen reaches the cells inside the body of this flatworm.
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Page 3

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1 (b) (ii) Describe how carbon dioxide in the air outside a leaf reaches mesophyll cells inside
the leaf.
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(3 marks)
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2 Sugar beet is a crop grown for the sugar stored in its root. The sugar is produced by
photosynthesis in the leaves of the plant. Plant breeders selected high-yielding wild
beet plants. They used these plants to produce a strain of sugar beet to grow as a
crop.
The drawings show a wild beet plant and a sugar beet plant. The drawings are to the
same scale.…read more

Page 5

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2 (b) Sugar beet plants have been selected for a faster rate of growth.
Suggest how the faster rate of growth may increase profit for a farmer.
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(1 mark)
2 (c) Describe and explain how selection will have affected the genetic diversity of sugar
beet.
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3 The diagram shows one end of a cellulose molecule.
H O O H H O O
Z H H O O H H
Bond Y
3 (a) (i) Name the monomers that form a cellulose molecule.
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(1 mark)
3 (a) (ii) Name bond Y.
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(1 mark)
3 (a) (iii) What chemical group is at position Z?
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3 (b) (i) Complete the table to show two ways in which the structure of cellulose is different
from the structure of starch.
Starch Cellulose
(2 marks)
3 (b) (ii) Explain one way in which the structure of cellulose is linked to its function.
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4 (a) Mitosis is important in the life of an organism. Give two reasons why.
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(2 marks)
A biologist used a microscope to investigate plant tissue where some of the cells were
dividing by mitosis. She examined 200 cells and counted the number of cells in
interphase and in each stage of mitosis.…read more

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4 (b) (i) Explain why the biologist chose to examine 200 cells.
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(1 mark)
4 (b) (ii) Name Stage A and Stage B. Give the evidence from the photograph that you used to
identify the stage.
Name of Stage A ...............................................................................................................
Evidence .............................................................................................................................
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Name of Stage B ...............................................................................................................
Evidence .............................................................................................................................
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(4 marks)
4 (c) In this tissue one complete cell cycle took 20 hours.…read more

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5 The diagram shows part of a DNA molecule.
C
D
E
5 (a) (i) DNA is a polymer. What is the evidence from the diagram that DNA is a polymer?
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(1 mark)
5 (a) (ii) Name the parts of the diagram labelled C, D and E.
Part C .......................................................................
Part D .......................................................................
Part E .......................................................................
(3 marks)
5 (a) (iii) In a piece of DNA, 34% of the bases were thymine.…read more

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