What volume of water is required to make up a 0.266moldm^-3 solution containing 4.04g of KNO3?

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any help would be appreciated :)

AS chemistry

Thanks,

Posted Wed 14th November, 2012 @ 19:33 by 94Y86

1 Answer

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n=mass/mr 4.04/16+16+16+39.1+14 =0.0399604351 moles

n=cv/1000

v of water =n1000/c

(0.0399604351)(1000)/0.266

V=150cm*3

Answered Sun 2nd December, 2012 @ 11:26 by Edward Pinches