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If you have any Core 2 questions, just post them here and I am will answer them for you with a detailed explanation of how to answer it.
ok I have a question:
Verify that x=2 is a root of the equation, (2x + 5)^4 - (2x - 5)^4 = 3680x - 800
I did it the method of using f(x) where x= 2 which worked as it equalled 0, but the mark scheme showed it just replacing the x in the brackets with 2, I thought you weren't allowed to do this?
I dont see why this a problem, to place the 2 within the brackets, to show that both sides are equal to 0.
Whats your reasoning to behind why it doesnt work?
well what I did was turn it into a cubic, I think I got 320x^3 - 1680x + 800 which cancelled down to 4x^3 - 21x + 10
then put the x = 2 into that
but I didn't think if you get a questions such as (x-3)^2 you cant just put the x in.. or can you?
Firstly how did you turn that into a cubic?
And also there is no need to turn it into anything else. All you have to do is look at what you have and substitute 2 in so that to see if it is a solution
Yeah you can just substitute it in. However there is no point doing it in the example you gave seeing as there is no solution to the question !
Yes there was a previous part to the question which I didn't write which allowed me to turn into a cubic.
Tbh this is a bit of an abiguous question and could answered in many different ways. So I wouldnt worry about it.
In the end of the day you have to pick the style that suits you best
I'll find you a really hard logs question to do as I can't do them at all!
a) sketch curve y = 6 multiplied by 5^x stating co-ordinates of any points of intersection with axes
b) point P on curve y = 9^x has co-ordinates equal to 150. Use logs to find x-coordinate of P
c) the curves y= 6 multiplied by 5^x and y=9^x intersect at Q. Show that x-coordinate of Q can be written as
x = 1+logv3 2/ 2-logv3 5
Cos I had no idea about section c of this.. :P
have a look at this, if you still dont get it message me !
ok I have something else :P
trying to find a and k, usually fine at algebra but I've reached a part the mark scheme can't help me realise..
I've got 4k^3a = 128 and ak = 2
but the mark scheme goes straight from the first equation to k^2 = 16.. how?! :S
don't worry, worked it out :)
Was this a logarithms questions? Good to know that you worked it out. Sorry I didnt reply, been a bit busy, got an exam tommorow :/
yep same! c2?
no it was D1. Was pretty difficult. Did you do it?
hey how do u answer these two a surd question s
1. 8√8 is equal to 8 to the power of x . what is x?
2.8√8 can also be written as m√2. what is m?
plzzzzzzzz help me as i don't really get surds..... reply soon x thnx
Im under the impression that this is a logarithm question as you have to solve for a power.
1. 8√8 = 8^x
log(1. 8√8) = log8^x
log(1. 8√8) = xlog8
x = log(1. 8√8 / log8)
2.8√8 = 2.8√4√2
2.8√8 = (2.8 x 2)√2
2.8√8 = 5.6√2
nope, I had c2 - was ok, but last questions didn't understand :/
We do stats instead of D1
Oh I do AS Further maths. Would have done the full A level but joined late because I didnt realise I enjoyed maths so muhc.
So I do C1, C2, C3, C4, M1, M2, S1, D1 and FP1 :)
Do you recon you done okay in the exam though?
You'll have to let me know the result you get. I'll let you know what i get as well.