# ok i got qs, pls pls answer this. 1) 25 cm3 of a solution of an acid HxA containing 0.1 mol dm3 of the acid in each 1000cm3 of solution reacts with 75cm3 of a solution of 0.1 mol dm3 NaOH. What is the value of x?

pls dont jst write the answer

Posted Sat 2nd June, 2012 @ 11:17 by Musllih

I don't understand, is this a maths or a chemistry question and what is the HxA?

Answered Sat 2nd June, 2012 @ 11:36 by Terrie

its a chem question , its just not a real substance, just need to find that value.
ps: i know its .......

Answered Sat 2nd June, 2012 @ 18:31 by Musllih

It's a chemistry question using moles.

You have 25cm3 of HxA at a concentration of 0.1mol.dm3.

Moles= Concentration x (Volume/1000)

Moles of HxA = 0.1 x (25/1000)

Moles of HxA = 0.0025 mol

You also use 75cm3 of NaOH at a concentration of 0.1mol.dm3

Moles of NaOH = 0.1 x (75/1000)

Moles of NaOH = 0,0075 mol

0.0075 / 0.0025 = 3     x=3

Answered Sun 3rd June, 2012 @ 16:49 by Amy

Hey @ Amy thnkx for da help but the answer should be X=2.
sum1 pls helpout?? :(

Answered Mon 4th June, 2012 @ 10:46 by Musllih

I found the answer to your question on this website. Its on Pg 102. I don't really understand it but you might!

http://www.xtremepapers.com/papers/IB/Chemistry/Resources/Moles%20Formulae%20workbook%20v3_V1.PDF

Answered Mon 4th June, 2012 @ 11:30 by Dilly

Ha ha this is it!
Thankx Dilly thanks a lot.
but still i dont understand the question anyways, how didi you find it?

Answered Tue 5th June, 2012 @ 09:26 by Musllih