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I'm really struggling to understand logarithms; could somebody explain this question to me?

Show that 2 log2 (x) = 2 + log2 (3x + 1) can be written as x^2 - 12x - 4 = 0

Posted Tue 26th November, 2013 @ 20:40 by Shannon Tennant-Smith - Team GR

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2log2(x)-2-log2(3x+1)=0

log2(x^2)-(log2(4)+log2(3x+1))=0

log2(x^2)-log2(12x+4)

x^2-(12x+4)=0

x^2-12x-4=0

Answered Tue 9th June, 2015 @ 14:31 by bob truma