Hi, I'm a bit stuck on a few simultaneous equation questions, please could I have some help?

1) y=x squared +2

y= x + 14

2) y= 1- 13x

y= 4x squared + 4

please help!

Posted Mon 18th June, 2012 @ 17:35 by

asdfghjkl
**Question one...**

y = x (^{2)} +2

y = x+ 14

*First rearrange to get x and y on one side and the numbers on the other...*

x(^{2) }- y = -2

x - y = 14

*Then because the symbols are the same you add the coefficient...*

2x(^{2 ) }= 12

*Divide both sides by 2...*

x(^{2}) = 6

*Square root answer... *

x = square root of 6

**I think i did something wrong, but this is the method of doing it.. sorry dude ! x**

Answered Mon 18th June, 2012 @ 17:46 by

? Secret - Team GREdited by

? Secret - Team GR on Mon 18th June, 2012 @ 17:47

BTW the 2 in bracket, is the square.. sorry if its confusing.. good luck !

Answered Mon 18th June, 2012 @ 17:48 by

? Secret - Team GR
1)

x(2) + 2 = x + 14

x(2) - x -12 = 0

(x - 4)(x + 3)

x=4 , x= -3

y= 4+14 y= -3+14

y= 18 when x=4 y=11 when x= -3

2)

1 - 13x = 4x(2) + 4

4x(2) +13x +3 =0

(4x+1)(x+3)

x= -1/4 , x= -3

y= 1- 13(-1/4) y= 1 -13(-3)

y= 17/4 when x= -1/4 y=40 when x= -3

Answered Mon 18th June, 2012 @ 19:30 by

Amy