How do you do simlutaneous equations?

Hi, I'm a bit stuck on a few simultaneous equation questions, please could I have some help?

1)   y=x squared +2

y= x + 14

2)  y= 1- 13x

y= 4x squared + 4

Posted Mon 18th June, 2012 @ 17:35 by asdfghjkl

Question one...

y = x (2) +2

y = x+ 14

First rearrange to get x and y on one side and the numbers on the other...

x(2) - y = -2

x - y = 14

Then because the symbols are the same you add the coefficient...

2x(2 )    = 12

Divide both sides by 2...

x(2)  = 6

x = square root of 6

I think i did something wrong, but this is the method of doing it.. sorry dude ! x

Answered Mon 18th June, 2012 @ 17:46 by ? Secret - Team GR
Edited by ? Secret - Team GR on Mon 18th June, 2012 @ 17:47

BTW the 2 in bracket, is the square.. sorry if its confusing.. good luck !

Answered Mon 18th June, 2012 @ 17:48 by ? Secret - Team GR

1)

x(2) + 2 = x + 14

x(2) - x -12 = 0

(x - 4)(x + 3)

x=4 , x= -3

y= 4+14    y= -3+14

y= 18 when x=4   y=11 when x= -3

2)

1 - 13x = 4x(2) + 4

4x(2) +13x +3 =0

(4x+1)(x+3)

x= -1/4 , x= -3

y= 1- 13(-1/4)  y= 1 -13(-3)

y= 17/4 when x= -1/4   y=40 when x= -3

Answered Mon 18th June, 2012 @ 19:30 by Amy