1) a curve is given by the equation y=3x^2 + 3 + 1/x^2 where x>0. at the points A,B AND C on the curve x=1,2 and 3 respectivley. find the gradients at A, B and C.

cud u please explain how u did it..thnx ^_^

Posted Tue 20th November, 2012 @ 19:04 by

Waqar Khanny :)Edited by

Waqar Khanny :) on Tue 20th November, 2012 @ 19:26

y=3x^2 + 3 + 1/x^2 = 3x^2 + 3 + x^-2 To differentiate you times by the power and minus 1 from the power.

dy/dx = 6x - 2x^-3

then sub in the x values

x = 1, gradient = 4

x = 2, gradient = 11.75

x= 3, gradient = 17.9259

hope this helps

Answered Wed 21st November, 2012 @ 14:32 by

Sophie
thank u sophie.... :P

it helped a lot XD

Answered Wed 21st November, 2012 @ 16:14 by

Waqar Khanny :)
find dy/dx and substitute the x values to it. :)

Answered Thu 22nd November, 2012 @ 15:01 by

Yohan
Answered Thu 22nd November, 2012 @ 16:18 by

Waqar Khanny :)