1) the point A (-1, -2) B (7, 2) and c (k, 4),  where k is a constant, are the vertices of triangle ABC. angle ABC is a right angle..

a) find the gradient of AB

b) calculate the value of k

c) find an equation of the straight line passing through B and C. give your answer in the form ax + by + c = 0 where a, b and c are intergers

cud u please explain how u did it......thnx 8)

Posted Tue 23rd October, 2012 @ 16:25 by Waqar Khanny :)

1) (y2 - y1) / (x2 - x1) = (2 - -2) / (7 - -1) = (2+2) / (7+1) = 4/8 = 1/2

2) BC is perpendicular to AB so the gradient is -2

(y2 - y1) / (x2 - x1) = (4 - 2) / (k - 7) = 2 / (k - 7)

2 / (k - 7) = -2

2 = -2(k - 7)

2 = -2k + 14

2k = 12

k = 7

c) y - y1 = m(x - x1)

y - 2 = -2(x - 7)

y - 2 = -2x + 14

y + 2x - 16 = 0

I think this is right, hope it helps!

Answered Tue 23rd October, 2012 @ 21:39 by Joanne

OMG THANX SOOOO MUCH I THOUGHT NO BODY WAZ GONNA HELP ME LOL U SAVED MY LYF AGAIN ^__^ THNX ((AGAIN)) LOL XDD

Answered Tue 23rd October, 2012 @ 21:41 by Waqar Khanny :)

Aha no problem! You doing the AQA exam board?

Answered Tue 23rd October, 2012 @ 21:47 by Joanne

noo edexcel LOL thnx again ^__~

Answered Tue 23rd October, 2012 @ 21:49 by Waqar Khanny :)

heeyyy cud u help me again please?

Answered Tue 23rd October, 2012 @ 21:55 by Waqar Khanny :)

Yeah what with?

Answered Wed 24th October, 2012 @ 09:40 by Joanne

ermm itz do do wiv statistis ===> how would you calculate if something was an outlier and what exactly is an outlier

Answered Wed 24th October, 2012 @ 19:37 by Waqar Khanny :)

An outlier is an anomaly - outside the main bulk of the data, a weird result. I think this might help - I'm not doing statistics and I can't remember much from GCSE sorry!

http://www.ehow.com/how_5201412_calculate-outliers.html

Answered Wed 24th October, 2012 @ 21:10 by Joanne

thnx annyywayyz ^__~

yeah u helped XDD

1 last question

1) given that (2x^2 - x3/2)/sqrt x  can be written in the form 2x^p - x^q

write down the value of p and the value of q

Answered Wed 24th October, 2012 @ 22:01 by Waqar Khanny :)