help!....

given that the equation kx^2 + 12x + k = 0, where k is a positive constant, has equal roots, find the value of k

Posted Sun 2nd December, 2012 @ 16:06 by Waqar Khanny :)

the answer to the question is on this link, K is 6, and X is -1, you have to use this equation in future:

Answered Sun 2nd December, 2012 @ 17:12 by Eamon Walker

Not sure if this is the right method as i kind of experimented with numbers and found that 6 worked. Because it had equal roots, I knew that when you factorise it, the brackets must be the same.

6x^2 + 12x + 6

6(x^2+2x+1)

6(x+1)(x+1)

Hope this helps and makes a bit of sense!

Answered Sun 2nd December, 2012 @ 16:43 by Sophie

wud i need 2 sketch a graph??

Answered Sun 2nd December, 2012 @ 22:40 by Waqar Khanny :)

no you wouldn't unless it specified or asked you to solve it graphically, you might want to ask your teacher on that one.

Answered Mon 3rd December, 2012 @ 10:35 by Eamon Walker

ok..thanx ^_^

Answered Mon 3rd December, 2012 @ 15:54 by Waqar Khanny :)