Can anyone solve this please?
- 0 votes
Variables t and N are such that when 1g N is plotted against 1g t, a straight line graph passing
through the points (0.45, 1.2) and (1, 3.4) is obtained.
(i) Express the equation of the straight line graph in the form 1g N = m 1g t + 1g c, where m and c
are constants to be found. (4)
(ii) Hence express N in terms of t. 
- 3 votes
a) you just put the coordinates into the equation and get simultanious equations which you can solve for m and c
So you get:
1.2 = 0.45m + 1g c
3.4 = 1m + 1g c
Then we can work out that 1g c by substitution
1g c = 1.2 - 0.45m
3.4 = m + 1.2 - 0.45m
2.2 = 0.55m
So 1g c = 1.2 - (0.45x4) = -0.6
Working out c is where i get stuck when we dont know what g is :/
b) So you know divide the whole equation by 1g gives you -
N = mt + c
N = 4t + (what ever you find out for c)
Sorry I couldn't help completely!