AS LEVEL: Radian Question on Core 2 Jan 11 Q8 i.

  • 0 votes

It tells you that Area of sector AOB = 8 and r (side of sector) = 5

You need to find the angle O.

I did : o.5 X r^2 X sin O = 8

rearrange to get  sin O= 0.64 (8 divided by o.5 X5^2)

so the angle is 0.64, right?

Answer says it is 0.694

Someone please figure this out, I don't understand how they got 0.694?!

Posted Sat 12th May, 2012 @ 11:10 by Shaimaa

4 Answers

  • 0 votes

Ohh, I just worked it out, you so sin^-1 (o.64) in radians mode.

Never mind, thanks anyway

Answered Sat 12th May, 2012 @ 11:16 by Shaimaa
  • 0 votes

yh sin to the minus one is the correct method alwayws remeber to to do the inverse operation when finding angles ** <3 x cn u email em anyway though so i can get to know u x if u dont mind x

Answered Sat 12th May, 2012 @ 11:18 by faizan rashid
  • -1 votes

yh shaima that is the correct method i went through the same qwuestion on a paper and i had a similiar one to this ** <3 ** shaimaa cn u mail me bk on [email protected] ** cheers i very much appreciate it x

Answered Sat 12th May, 2012 @ 11:15 by faizan rashid
  • -1 votes

An area of a sector is n divided by 360 degrees times by pie times r squared  thats the formula i used to do this **

Answered Sat 12th May, 2012 @ 11:17 by faizan rashid